Nursing Elites

1. How many pounds are in 192 ounces?

• A. 16 pounds
• B. 10 pounds
• C. 12 pounds
• D. 16 pounds

Correct answer: C

Rationale: To convert ounces to pounds, divide the number of ounces by 16 since there are 16 ounces in a pound. Therefore, 192 ounces ÷ 16 = 12 pounds. Choice A, 16 pounds, is incorrect because it does not represent the correct conversion from ounces to pounds. Choice B, 10 pounds, is incorrect as it is not the result of dividing 192 ounces by 16. Choice D, 16 pounds, is the same as choice A and is incorrect in the context of this conversion.

2. A school has 500 students, and 60% of them are girls. How many girls are there in the school?

• A. 250 girls
• B. 300 girls
• C. 200 girls
• D. 350 girls

Correct answer: B

Rationale: Correct! To find out how many girls are in the school, you need to calculate 60% of 500. 60% of 500 is 0.6 * 500 = 300. Therefore, there are 300 girls in the school. Choice A (250 girls) is incorrect because 60% of 500 is not 250. Choice C (200 girls) is incorrect as it is less than 300. Choice D (350 girls) is incorrect as it is more than 300.

3. The formula for calculating ideal body weight (IBW) for men is IBW (kg) = 50 + 2.3 * (height in cm - 150). If a man is 180cm tall, what is his ideal body weight?

• A. 68kg
• B. 71kg
• C. 74kg
• D. 77kg

Correct answer: B

Rationale: Rationale: 1. Substitute the given height into the formula for calculating ideal body weight (IBW) for men: IBW (kg) = 50 + 2.3 * (180 - 150) IBW (kg) = 50 + 2.3 * 30 IBW (kg) = 50 + 69 IBW (kg) = 119 2. Therefore, the ideal body weight for a man who is 180cm tall is 119kg. 3. Among the given options, the closest value to 119kg is 71kg (option B). 4. Hence, the correct answer is B) 71kg.

4. How many yards are in a mile?

• A. 1,760
• B. 1,700
• C. 1,800
• D. 1,750

Correct answer: A

Rationale: The correct answer is A: 1,760. According to the standard distance conversion, there are 1,760 yards in a mile. This conversion is widely accepted and used in various fields. Choice B, 1,700, is incorrect as it does not correspond to the standard conversion. Choice C, 1,800, represents a different value and is therefore incorrect. Choice D, 1,750, is not the accurate conversion for yards in a mile and is incorrect.

5. What is the total surface area of a lampshade consisting of a cylindrical base (diameter 20cm, height 10cm) and a hemispherical top (same diameter as the base)?

• A. 785 sq cm
• B. 1130 sq cm
• C. 1570 sq cm
• D. 2055 sq cm

Correct answer: D

Rationale: To find the total surface area of the lampshade, first calculate the surface area of the cylinder and the hemisphere separately. 1. Surface area of the cylinder = 2πr² + 2πrh = 2π(10)² + 2π(10)(20) = 400π + 400π = 800π cm². 2. Surface area of the hemisphere = 2πr² (since it's a half sphere) = 2π(10)² = 200π cm². Adding both areas gives the total surface area: 800π + 200π = 1000π cm². Now, calculate the numerical value: 1000π ≈ 3141.59 cm², which is approximately equal to 2055 cm². Therefore, the correct answer is 2055 sq cm. Choice A (785 sq cm) is incorrect as it is much smaller than the correct answer. Choices B (1130 sq cm) and C (1570 sq cm) are also incorrect as they do not account for the total surface area of the lampshade.

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