Nursing Elites

1. An ancient Egyptian pyramid has a square base with side lengths of 20 meters and a remaining height (after erosion) of 10 meters. Its original height was 30 meters. What was the volume of the pyramid in its original state?

• A. 12000 cubic meters
• B. 6000 cubic meters
• C. 18000 cubic meters
• D. 24000 cubic meters

Correct answer: A

Rationale: To find the volume of a pyramid, you can use the formula: Volume = (1/3) * base area * height. In this case, the base area is the square of side length 20 meters, which is 20 * 20 = 400 square meters. The original height of the pyramid is 30 meters. Therefore, the volume of the pyramid in its original state is (1/3) * 400 * 30 = 12000 cubic meters. Choice A is correct. Choices B, C, and D are incorrect as they do not correctly calculate the volume using the original height and base area of the pyramid.

2. How many ounces are in 1.5 quarts?

• A. 32 ounces
• B. 16 ounces
• C. 48 ounces
• D. 64 ounces

Correct answer: C

Rationale: To convert quarts to ounces, you multiply the number of quarts by the conversion factor of 32 (since there are 32 ounces in a quart). Therefore, 1.5 quarts is equal to 1.5 x 32 = 48 ounces. The correct answer is 48 ounces. Choice A (32 ounces) is incorrect as it represents the amount of ounces in 1 quart, not 1.5 quarts. Choice B (16 ounces) is incorrect as it is half the amount of ounces in 1 quart. Choice D (64 ounces) is incorrect as it represents the amount of ounces in 2 quarts, not 1.5 quarts.

3. The order of operations (PEMDAS) dictates the sequence for evaluating mathematical expressions. If a = 2 and b = -3, what is the value of 3a^2 - 2ab + b^2?

• A. -3
• B. 0
• C. 33
• D. 15

Correct answer: C

Rationale: Given expression: 3a^2 - 2ab + b^2. Substitute the values of a and b: 3(2)^2 - 2(2)(-3) + (-3)^2 = 3(4) + 12 + 9 = 12 + 12 + 9 = 24 + 9 = 33. Therefore, the value of the expression is 33, which corresponds to option C. Options A, B, and D are incorrect as they do not accurately evaluate the expression with the given values of a and b.

4. What event occurs during telophase?

• A. The nuclear envelope disappears.
• B. Organelles double in number.
• C. Chromosomes separate.
• D. Two nuclei are formed.

Correct answer: D

Rationale: During telophase, the final stage of mitosis, the separated chromosomes reach opposite poles of the cell. At this stage, a new nuclear envelope forms around each set of chromosomes, creating two distinct nuclei. This marks the completion of cell division. Choices A, B, and C are incorrect because the disappearance of the nuclear envelope typically occurs during prophase, organelles do not double in number during telophase, and chromosomes separate during anaphase, not telophase.

5. Subtract 28 3/4 - 5 5/6.

• A. 22 & 11/12
• B. 23 & 1/2
• C. 34 & 1/12
• D. 22 & 2/3

Correct answer: A

Rationale: To subtract mixed numbers, find a common denominator. Convert 28 3/4 to 28 9/12. Then, subtract 5 5/6 from 28 9/12 to get 22 11/12. Therefore, 28 3/4 - 5 5/6 = 22 & 11/12, which matches choice A. Choices B, C, and D are incorrect because they do not reflect the correct subtraction result after finding the common denominator and performing the subtraction.

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