a train leaves the station at 145 pm traveling at a constant speed of 65 mph if it arrives at its destination at 315 pm how many miles did it travel
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HESI A2

Math HESI A2 Practice Test

1. A train leaves the station at 1:45 PM traveling at a constant speed of 65 mph. If it arrives at its destination at 3:15 PM, how many miles did it travel?

Correct answer: A

Rationale: To calculate the distance traveled by the train, multiply the speed (65 mph) by the time it took to reach the destination, which is 1.5 hours (3:15 PM - 1:45 PM = 1.5 hours). Therefore, 65 mph × 1.5 hours = 97.5 miles. This calculation is correct because distance = speed × time. Choices B, C, and D are incorrect as they do not reflect the correct calculation based on the given information.

2. Solve for x: x/5 = 3/10.

Correct answer: D

Rationale: To solve for x when x/5 = 3/10, you need to cross-multiply. This gives you 10x = 5 × 3. Simplifying further, you get x = 15/10, which reduces to x = 1.5. Therefore, the correct answer is x = 1.5. Choices A, B, and C are incorrect because they do not match the correct calculation for x.

3. A die is rolled. What is the probability of getting 5?

Correct answer: A

Rationale: The correct answer is A: 16.67%. When rolling a standard 6-sided die, each face has an equal probability of 1/6. Therefore, the probability of rolling a 5 specifically is 1/6, which is approximately 16.67% when converted to a percentage. Choices B, C, and D are incorrect because they do not reflect the correct probability of rolling a 5 on a standard die.

4. If Kevin can wash 30 cars in 15 minutes, how many minutes will it take him to wash 100 cars?

Correct answer: A

Rationale: To find out how many minutes Kevin will take to wash 100 cars, set up a proportion: 30 cars is to 15 minutes as 100 cars is to x minutes. Cross multiplying gives 30x = 1500. Solving for x, x = 1500 / 30 = 50. Therefore, it will take Kevin 50 minutes to wash 100 cars. Choice A is correct. Choice B, C, and D are incorrect as they do not correctly calculate the time needed based on the given information.

5. A solution is 60% alcohol. If 200ml of the solution is used, how much pure alcohol is present?

Correct answer: B

Rationale: If the solution is 60% alcohol, it means that 60% of the solution is alcohol. Therefore, in 200ml of the solution, the amount of alcohol present is: 200ml * 60% = 200ml * 0.60 = 120ml. So, when 200ml of the solution is used, there are 120ml of pure alcohol present. Choice A, 100ml, is incorrect because it does not account for the correct percentage of alcohol in the solution. Choice C, 140ml, and Choice D, 160ml, are incorrect as they overestimate the amount of pure alcohol present in the solution.

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