Nursing Elites

1. A table shows the average blood pressure readings for different age groups. How do you determine the highest average systolic pressure?

• A. Find the largest number in the "systolic pressure" column.
• B. Compare the means (averages) of each age group.
• C. Add all systolic pressure values and divide by the total number of patients.
• D. Subtract the lowest systolic pressure from the highest.

Correct answer: A

Rationale: Rationale: - To determine the highest average systolic pressure, you need to identify the highest individual systolic pressure reading in the dataset. - Option A instructs you to find the largest number in the "systolic pressure" column, which directly addresses the task of identifying the highest systolic pressure reading. - Comparing means (Option B) would not necessarily give you the highest individual systolic pressure reading, as averages can be influenced by the distribution of values within each age group. - Adding all systolic pressure values and dividing by the total number of patients (Option C) would give you the overall average systolic pressure, not the highest individual reading. - Subtracting the lowest systolic pressure from the highest (Option D) would give you the range of systolic pressures, not specifically the highest individual reading. Therefore, the correct approach to determine the highest average systolic pressure

2. Solve for x: 3x + 9 = 0.

• A. x = -3
• B. x = -3
• C. x = 1
• D. x = 0

Correct answer: B

Rationale: To solve the equation 3x + 9 = 0, first, isolate the variable x. Subtract 9 from both sides to get 3x = -9. Then, divide by 3 to solve for x, giving x = -3. Therefore, the correct answer is B. Choice A, x = -3, is the correct solution. Choices C and D are incorrect as they do not satisfy the equation when substituted back into it.

3. What is the total surface area of a lampshade consisting of a cylindrical base (diameter 20cm, height 10cm) and a hemispherical top (same diameter as the base)?

• A. 785 sq cm
• B. 1130 sq cm
• C. 1570 sq cm
• D. 2055 sq cm

Correct answer: D

Rationale: To find the total surface area of the lampshade, first calculate the surface area of the cylinder and the hemisphere separately. 1. Surface area of the cylinder = 2πr² + 2πrh = 2π(10)² + 2π(10)(20) = 400π + 400π = 800π cm². 2. Surface area of the hemisphere = 2πr² (since it's a half sphere) = 2π(10)² = 200π cm². Adding both areas gives the total surface area: 800π + 200π = 1000π cm². Now, calculate the numerical value: 1000π ≈ 3141.59 cm², which is approximately equal to 2055 cm². Therefore, the correct answer is 2055 sq cm. Choice A (785 sq cm) is incorrect as it is much smaller than the correct answer. Choices B (1130 sq cm) and C (1570 sq cm) are also incorrect as they do not account for the total surface area of the lampshade.

4. How many cakes do you need for a class of 70 students and 3 staff members if each cake provides 24 servings?

• A. 4
• B. 2
• C. 5
• D. 3

Correct answer: A

Rationale: To determine the number of cakes needed, calculate the total number of people, which is 70 students + 3 staff = 73 people. Since each cake serves 24 people, divide the total number of people by 24 to get approximately 3.04. You cannot have a fraction of a cake, so round up to the next whole number, which is 4. Therefore, you need 4 cakes to serve the class of 70 students and 3 staff members. Choice B (2) is incorrect because 2 cakes would not be enough to serve 73 people. Choice C (5) is incorrect as it would be an excess of cakes. Choice D (3) is incorrect because 3 cakes would not be sufficient to serve 73 people.

5. Richard wants to make 2.5 batches of sugar cookies. One batch calls for 1.75 cups of sugar. How many cups of sugar will Richard need for 2.5 batches?

• A. 4
• B. 3
• C. 5 cups
• D. 3

Correct answer: A

Rationale: To calculate how much sugar Richard needs for 2.5 batches, multiply the amount of sugar needed for one batch (1.75 cups) by 2.5: 1.75 × 2.5 = 4.375  cups 1.75×2.5=4.375 cups Since the question is asking for the nearest whole number, 4.375 rounds to 4.

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