HESI A2
HESI A2 Math Portion
1. A lab needs 200ml of a 5% salt solution. They only have a 10% solution. How much 10% solution and water should be mixed?
- A. 100ml 10% solution, 100ml water
- B. 150ml 10% solution, 50ml water
- C. 160ml 10% solution, 40ml water
- D. 200ml 10% solution, 0ml water
Correct answer: B
Rationale: Rationale: 1. Let x be the volume of the 10% solution needed and y be the volume of water needed. 2. The total volume of the final solution is 200ml, so x + y = 200. 3. The concentration of the final solution is 5%, so the amount of salt in the final solution is 0.05 * 200 = 10g. 4. The amount of salt in the 10% solution is 0.1x, and the amount of salt in the water is 0, so the total amount of salt in the final solution is 0.1x. 5. Since the total amount of salt in the final solution is 10g, we have 0.1x = 10. 6. Solving for x, we get x = 100ml. 7. Substituting x =
2. How many milliliters are in 6 liters?
- A. 60 milliliters
- B. 6000 milliliters
- C. 600 milliliters
- D. 0.6 milliliters
Correct answer: B
Rationale: The correct answer is B: 6000 milliliters. There are 1,000 milliliters in a liter. To convert liters to milliliters, you multiply the number of liters by 1,000. Therefore, 6 liters = 6 × 1,000 = 6,000 milliliters. Choices A, C, and D are incorrect because they do not correctly convert liters to milliliters.
3. Solve for x: x + 44 / 2x = 11.
- A. 13
- B. 33
- C. 55
- D. 2.5
Correct answer: A
Rationale: To solve the equation x + 44 / 2x = 11, first, divide 44 by 2x to simplify it to x + 22/x = 11. Multiply through by x to clear the fraction, resulting in x^2 + 22 = 11x. Rearrange the terms to get x^2 - 11x + 22 = 0. Factor the quadratic equation to (x - 11)(x - 2) = 0. Therefore, x = 11 or x = 2. However, x cannot be 2 as it would make the denominator zero. Hence, x = 13. The correct answer is 13. Choice B (33) is incorrect as it is not a solution to the equation. Choice C (55) is incorrect as it is not a solution to the equation. Choice D (2.5) is incorrect as it is not a whole number and does not satisfy the equation.
4. Sally was able to eat 5/8 of her lunch. John ate 75% of his lunch. Who ate more?
- A. John
- B. Sally
- C. Both ate the same
- D. Cannot be determined
Correct answer: A
Rationale: To compare the portions eaten by Sally and John, it's necessary to express both in the same denominator. Since 75% is equivalent to 6/8, John ate 6/8 while Sally ate 5/8 of their lunches. Therefore, John ate more than Sally. Choice A is correct. Choice B is incorrect as John ate 6/8 compared to Sally's 5/8. Choice C is incorrect as the amounts eaten are different. Choice D is incorrect as it can be determined based on the given information.
5. Convert the following military time to regular time: 15:17:52.
- A. 2:17 PM
- B. 3:17 PM
- C. 5:17 AM
- D. 9:17 AM
Correct answer: B
Rationale: To convert military time to regular time, subtract 12 from the hours if it is 13 or greater. In this case, 15:17:52 becomes 3:17:52 PM. Choice A (2:17 PM) is incorrect as it doesn't adjust for the 12-hour conversion. Choice C (5:17 AM) and Choice D (9:17 AM) are incorrect as they don't reflect the correct conversion from military time to regular time.
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