HESI A2
HESI A2 Math Portion
1. A lab needs 200ml of a 5% salt solution. They only have a 10% solution. How much 10% solution and water should be mixed?
- A. 100ml 10% solution, 100ml water
- B. 150ml 10% solution, 50ml water
- C. 160ml 10% solution, 40ml water
- D. 200ml 10% solution, 0ml water
Correct answer: B
Rationale: Rationale: 1. Let x be the volume of the 10% solution needed and y be the volume of water needed. 2. The total volume of the final solution is 200ml, so x + y = 200. 3. The concentration of the final solution is 5%, so the amount of salt in the final solution is 0.05 * 200 = 10g. 4. The amount of salt in the 10% solution is 0.1x, and the amount of salt in the water is 0, so the total amount of salt in the final solution is 0.1x. 5. Since the total amount of salt in the final solution is 10g, we have 0.1x = 10. 6. Solving for x, we get x = 100ml. 7. Substituting x =
2. How many grams are in 5 kilograms?
- A. 50,000 grams
- B. 500 grams
- C. 5,000 grams
- D. 50,000 grams
Correct answer: C
Rationale: The correct answer is C: 5,000 grams. There are 1,000 grams in a kilogram. Therefore, to convert kilograms to grams, you need to multiply the number of kilograms by 1,000. In this case, 5 kilograms is equal to 5 × 1,000 = 5,000 grams. Choices A and D are incorrect as they incorrectly multiply by 10,000 instead of 1,000. Choice B is incorrect as it divides instead of multiplies, leading to an incorrect conversion.
3. What is the freezing point of water in degrees Celsius?
- A. 0°C
- B. 100°C
- C. 50°C
- D. 25°C
Correct answer: A
Rationale: The correct answer is 0°C. The freezing point of water is 0°C under standard conditions. Water freezes at 0°C and boils at 100°C. Choices B, C, and D are incorrect because they do not represent the freezing point of water. 100°C is the boiling point of water, 50°C and 25°C are not related to the freezing point of water.
4. Convert 2100 to standard time.
- A. 12:00 PM
- B. 2:00 AM
- C. 9:00 PM
- D. 2:00 PM
Correct answer: C
Rationale: Military time is based on a 24-hour clock. To convert 2100 hours to standard time, subtract 1200 from the time if it is greater than or equal to 1300. In this case, 2100 - 1200 = 900, which corresponds to 9:00 PM in standard time. Choice A, 12:00 PM, is incorrect because 2100 is in the evening, not noon. Choice B, 2:00 AM, is incorrect as it represents the early morning hours. Choice D, 2:00 PM, is incorrect as it is in the afternoon, not the evening.
5. Divide: 92 ÷ 11 =
- A. 8 r3
- B. 8 r4
- C. 8 r7
- D. 9 r1
Correct answer: B
Rationale: To divide 92 by 11, you get 8 as the whole number part of the quotient. The remainder is 4, so the correct answer is 8 r4. Choice A, 8 r3, is incorrect because the remainder is 4, not 3. Choice C, 8 r7, is incorrect as the remainder cannot be greater than the divisor. Choice D, 9 r1, is incorrect as the whole number part of the quotient is 8, not 9.
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