Nursing Elites

1. Which of the following is not typically considered one of the main mechanisms of Type II Diabetes treatment?

• A. Medications
• B. Nutrition
• C. Increased activity
• D. Continuous Insulin

Correct answer: D

Rationale: Continuous Insulin is not typically considered one of the main mechanisms for treating Type II Diabetes. While medications, nutrition, and increased activity play crucial roles in managing Type II Diabetes, continuous insulin therapy is more common in Type I Diabetes or in specific cases of Type II Diabetes where other treatments are ineffective. Therefore, the correct answer is Continuous Insulin. Choices A, B, and C are mainstays in the treatment of Type II Diabetes, making them incorrect answers.

2. A client has a 10% dextrose in water IV solution running. He is scheduled to receive his antiepileptic drug, phenytoin (Dilantin), at this time. The nurse knows that the phenytoin:

• A. is given after the D10W is finished.
• B. should be given at the time it is due in the medication port closest to the client.
• C. can be piggybacked into the D10W solution now.
• D. is incompatible with dextrose solutions.

Correct answer: D

Rationale: Phenytoin is incompatible with dextrose solutions as they will precipitate when mixed together. Therefore, it should not be piggybacked into the D10W solution or given through the same port. Instead, normal saline should be used to flush before and after administering phenytoin to prevent any interaction with the dextrose solution. Delaying the administration of an antiepileptic drug like phenytoin to maintain therapeutic blood levels is not recommended, so it should not be given after the D10W is finished or based on the medication port closest to the client. Choice A is incorrect because administering phenytoin after the D10W is finished is not the correct approach due to the incompatibility with dextrose solutions. Choice B is incorrect as the timing of phenytoin administration should not be based on the medication port closest to the client but on compatibility considerations. Choice C is incorrect as piggybacking phenytoin into the D10W solution is not advisable due to the incompatibility issue.

3. The PN is caring for a client with diabetes insipidus. The nurse can expect the lab work to show:

• A. elevated urine osmolarity and elevated serum osmolarity.
• B. decreased urine osmolarity and decreased serum osmolarity.
• C. elevated urine osmolarity and decreased serum osmolarity.
• D. decreased urine osmolarity and elevated serum osmolarity.

Correct answer: D

Rationale: In diabetes insipidus, the pituitary releases too much antidiuretic hormone (ADH), causing the client to produce a large amount of dilute urine (decreased osmolarity) and leading to dehydration (elevated serum osmolarity). Therefore, the correct answer is decreased urine osmolarity and elevated serum osmolarity. Choice C, elevated urine osmolarity and decreased serum osmolarity, is incorrect for diabetes insipidus, as it is more characteristic of syndrome of inappropriate ADH (SIADH). Choices A and B, elevated urine osmolarity and elevated serum osmolarity, and decreased urine osmolarity and decreased serum osmolarity, respectively, are generally not seen in diabetes insipidus, as urine and serum osmolarity typically move in opposite directions in this condition.

4. Teaching about the importance of avoiding foods high in potassium is most crucial for which client?

• A. a client receiving diuretic therapy
• B. a client with an ileostomy
• C. a client with metabolic alkalosis
• D. a client with renal disease

Correct answer: D

Rationale: Clients with renal disease are prone to hyperkalemia due to impaired kidney function, making it crucial for them to avoid foods high in potassium to prevent further complications. Choices A, B, and C are incorrect because clients receiving diuretic therapy, with an ileostomy, or with metabolic alkalosis are at risk of hypokalemia. These individuals should actually consume foods high in potassium to replenish the electrolyte lost through diuresis, ileostomy output, or metabolic alkalosis.

5. Chemotherapeutic agents often produce a degree of myelosuppression including leukopenia. Leukopenia does not present immediately but is delayed several days or weeks because:

• A. the client's hemoglobin and hematocrit are normal.
• B. red blood cells are affected first.
• C. folic acid levels are normal.
• D. the current white cell count is not affected by chemotherapy.

Correct answer: D

Rationale: Leukopenia does not present immediately after chemotherapy because time is required to clear circulating cells before the effect on precursor cell maturation in the bone marrow becomes evident. Leukopenia is characterized by an abnormally low white blood cell count. The correct answer is D because the white cell count is not immediately affected by chemotherapy. Choices A, B, and C are incorrect as they pertain to red blood cells (hemoglobin and hematocrit), which are not directly related to the delayed onset of leukopenia.

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