Nursing Elites

1. What type of cells create exocrine secretions?

• A. alpha cells
• B. beta cells
• C. acinar cells
• D. plasma cells

Correct answer: C

Rationale: Acinar cells are responsible for creating exocrine secretions, such as enzymes and digestive juices. Alpha cells are found in the pancreas and are responsible for producing glucagon, beta cells produce insulin, and plasma cells are a type of white blood cell involved in immune responses. Therefore, the correct answer is acinar cells, as they specifically produce exocrine secretions.

2. A nurse is instructing a patient about the warning signs of Digitalis side effects. Which of the following side effects should the nurse tell the patient are sometimes associated with excessive levels of Digitalis?

• A. Seizures
• B. Muscle weakness
• C. Depression
• D. Anxiety

Correct answer: B

Rationale: The correct answer is 'Muscle weakness.' Palpitations and muscle weakness are commonly associated with excessive levels of Digitalis. Seizures, depression, and anxiety are not typically linked to Digitalis toxicity. Seizures could be more related to other medications or conditions, while depression and anxiety are not commonly reported side effects of Digitalis.

3. Which sexually transmitted disease, sometimes referred to as the silent STD, is more common than gonorrhea and a leading cause of PID?

• A. Genital herpes.
• B. Trichomoniasis.
• C. Syphilis.
• D. Chlamydia.

Correct answer: D

Rationale: The correct answer is Chlamydia. Chlamydia is a common sexually transmitted infection that can often be asymptomatic, earning it the nickname 'silent STD.' It is more common than gonorrhea and is a leading cause of Pelvic Inflammatory Disease (PID). Genital herpes (Choice A) is a viral infection, not a bacterial STD like chlamydia. Trichomoniasis (Choice B) is a parasitic infection and not commonly associated with causing PID. Syphilis (Choice C) is a bacterial infection but is not as common as chlamydia and is not a leading cause of PID.

4. Which of the following arterial blood gas values indicates a patient may be experiencing a condition of metabolic acidosis?

• A. PaO2 90 mm Hg
• B. Bicarbonate 15 mEq/L
• C. CO2 47 mm Hg
• D. pH 7.34

Correct answer: B

Rationale: The correct answer is B: Bicarbonate 15 mEq/L. In metabolic acidosis, the bicarbonate levels are lower than normal. A bicarbonate value of 15 mEq/L indicates a deficit in the buffer system, contributing to the acidosis. Choices A, C, and D are incorrect. Choice A, PaO2 90 mm Hg, reflects oxygen partial pressure and is not directly related to metabolic acidosis. Choice C, CO2 47 mm Hg, represents carbon dioxide levels and is more indicative of respiratory status. Choice D, pH 7.34, falls within the normal range (7.35-7.45) and does not confirm metabolic acidosis.

5. A client delivered a term male infant four hours ago. The infant was stillborn. Which room assignment would be most appropriate for this client?

• A. Request a private room on the GYN floor
• B. Assign her to a private room on the postpartum unit
• C. Discharge her home as soon as her condition is stable
• D. Room her with another client who experienced a pregnancy loss

Correct answer: A

Rationale: In this situation, the most appropriate room assignment for the client who delivered a stillborn infant would be to request a private room on the GYN floor. This client needs privacy to grieve, and having a private space allows for family members to offer support. Placing her in a GYN unit ensures that she is away from the maternity unit's sights and sounds, which could be painful reminders for her. Assigning her to a postpartum unit may cause distress due to the presence of other mothers and newborns. Discharging her home too early may not allow her sufficient time for emotional and physical recovery. Rooming her with another client who experienced a pregnancy loss may not provide the necessary privacy and space she needs for her emotional well-being.

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