a clinic nurse interviews a parent who is suspected of abusing her child which of the following characteristics is the nurse least likely to find in a
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NCLEX-RN

NCLEX RN Exam Questions

1. A clinic nurse interviews a parent who is suspected of abusing her child. Which of the following characteristics is the nurse least likely to find in an abusing parent?

Correct answer: C

Rationale: The profile of a parent at risk of abusive behavior includes a tendency to blame the child or others for the injury sustained. Abusers typically blame others, especially their partners, for the mistakes in their lives. This is related to hypersensitivity, but they are not necessarily alike. This occurs because most abusive people don't hold themselves as being accountable for the actions they commit. Instead, they'll try to shift the blame to the person that they have abused and somehow say they "deserved it"? or that they were forced into a corner.

2. The healthcare provider is reviewing the lab results of a patient who has presented in the Emergency Room. The lab results show that the troponin T value is at 5.3 ng/mL. Which of these interventions, if not already completed, would take priority over the others?

Correct answer: C

Rationale: In this scenario, the elevated Troponin T level indicates cardiac damage, possibly due to a myocardial infarction. A Troponin T value of 5.3 ng/mL is significantly elevated (normal levels are below 0.2 ng/mL), suggesting acute cardiac injury. Given the setting of an Emergency Room and the critical nature of the situation, the priority intervention should be to obtain and attach defibrillator leads. Elevated Troponin T levels can indicate a higher risk of arrhythmias, including ventricular fibrillation, which can lead to sudden cardiac arrest. Defibrillator leads are essential for monitoring the patient's cardiac rhythm and readiness for immediate defibrillation if necessary. Placing the patient in a 90-degree position (Choice A) or assessing diuretic use (Choice B) are not immediate priorities in this critical situation. Additionally, assessing the patient's last ejection fraction (Choice D) is important but not as urgent as preparing for potential life-threatening arrhythmias requiring defibrillation.

3. When caring for a patient hospitalized with active tuberculosis (TB), the nurse observes a student nurse who is assigned to take care of the patient. Which action, if performed by the student nurse, would require an intervention by the nurse?

Correct answer: B

Rationale: When caring for a patient with active tuberculosis (TB), it is crucial to use a high-efficiency particulate-absorbing (HEPA) mask instead of a standard surgical mask when entering the patient's room, as a HEPA mask can filter out 100% of small airborne particles, reducing the risk of transmission. Therefore, if the student nurse applies only a surgical face mask before visiting the patient, this action would require intervention by the nurse to ensure the appropriate protective equipment is used. Hand washing before entering the patient's room is essential to prevent the spread of infection and is a correct action. Bringing a snack to the patient from the unit refrigerator is appropriate and helps address potential issues with anorexia and weight loss in patients with TB. While hand washing after handling a tissue used by the patient is necessary, no special precautions are required when offering the patient an unused tissue.

4. Following mitral valve replacement surgery, a client develops PVCs. The healthcare provider orders a bolus of Lidocaine followed by a continuous Lidocaine infusion at a rate of 2 mg/minute. The IV solution contains 2 grams of Lidocaine in 500 mL of D5W. The infusion pump delivers 60 microdrops/mL. What rate would deliver 4 mg of Lidocaine per minute?

Correct answer: A

Rationale: To calculate the rate needed to deliver 4 mg/minute of Lidocaine, first, convert 2 grams to milligrams: 2 grams = 2000 mg. Then, set up a ratio between the total amount of Lidocaine (2000 mg) and the total volume of IV solution (500 mL): 2000 mg / 500 mL = 4 mg / x mL. Solving for x, x = 1 mL. Since the infusion pump delivers 60 microdrops per mL, multiplying by 60 microdrops/mL gives the correct rate of 60 microdrops/minute. This rate ensures the desired 4 mg of Lidocaine is delivered per minute. Choices B, C, and D are incorrect as they do not align with the accurate calculation based on the provided information.

5. You are responsible for reviewing the nursing unit's refrigerator. Which of the following drugs, if found inside the fridge, should be removed?

Correct answer: A

Rationale: Nadolol (Corgard) should be removed if found inside the fridge because it is supposed to be stored at room temperature between 59 to 86 �F (15 and 30 �C) away from heat, moisture, and light. Storing it in the refrigerator can alter its effectiveness and stability. Option B, the opened Humulin N injection, should not be stored in the refrigerator as it is an in-use product and can remain at room temperature for a certain period as per manufacturer guidelines. Option C, Urokinase (Kinlytic), and Option D, Epoetin alfa IV (Epogen), do not require refrigeration and can be stored at room temperature. Therefore, Nadolol (Corgard) is the drug that should be removed from the fridge.

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