1. Dendrites are finger-like extensions found on

A. Muscle cells
B. Connective tissue cells
C. Neurons
D. Epithelial cells

Correct answer: C

Rationale: Dendrites are the primary sites for receiving signals in a neuron. They are specialized extensions that branch out from the cell body of a neuron to receive incoming information from other neurons. These finger-like projections play a crucial role in transmitting electrical impulses and communication within the nervous system. Muscle cells, connective tissue cells, and epithelial cells do not have dendrites as they are not involved in neuronal communication.

2. What checkpoint mechanism ensures all chromosomes are attached to the spindle fibers before anaphase begins?

A. Prometaphase
B. Prometaphase
C. Cyclin degradation
D. Sister chromatid cohesion

Correct answer: A

Rationale: Rationale: A) Prometaphase is the correct answer because it is the stage of mitosis where all chromosomes are attached to the spindle fibers before anaphase begins. During prometaphase, the nuclear envelope breaks down, allowing the spindle fibers to attach to the kinetochores of the chromosomes. This attachment is necessary for proper chromosome alignment and segregation during anaphase. B) Metaphase is incorrect because it is the stage where chromosomes are aligned at the metaphase plate but do not necessarily have all spindle fibers attached. C) Cyclin degradation is incorrect because it is a regulatory mechanism that controls the progression of the cell cycle but is not specifically related to ensuring all chromosomes are attached to spindle fibers. D) Sister chromatid cohesion is incorrect because it refers to the physical connection between sister chromatids that is maintained until anaphase, but it does not ensure that all chromosomes are attached to spindle fibers.

3. Which of the following colligative properties refers to the elevation of the boiling point of a solution?

A. Freezing point depression
B. Vapor pressure lowering
C. Osmotic pressure
D. Boiling point elevation

Correct answer: A

Rationale: The correct answer is A: Freezing point depression. Colligative properties are properties that depend on the number of solute particles in a solution, not the type of solute. Freezing point depression is the phenomenon where the freezing point of a solvent is lowered when a solute is added, while boiling point elevation is the opposite effect where the boiling point of a solution is raised. Therefore, the question specifically asked for the colligative property that refers to the elevation of the boiling point, making "Freezing point depression" the correct answer.

4. The author likely intended to use the phrase "interconnected sensors" to emphasize...

A. The cost-effectiveness of smart city technology.
B. The complexity and network-based nature of the system.
C. The potential for environmental harm of sensor installation.
D. The aesthetic appeal of modern urban infrastructure.

Correct answer: B

Rationale: "Interconnected" highlights the integration and communication between sensors, indicating a complex network approach.

5. Which type of epithelium lines the inner surface of blood vessels?

A. Simple squamous epithelium
B. Simple columnar epithelium
C. Stratified squamous epithelium
D. Stratified columnar epithelium

Correct answer: A

Rationale: The correct answer is A. Simple squamous epithelium lines the inner surface of blood vessels due to its thin structure and ability to facilitate easy diffusion of gases and nutrients between blood and surrounding tissues. This type of epithelium is well suited for areas where rapid exchange of materials is important, such as the lining of blood vessels. Simple columnar epithelium is typically found in areas where absorption and secretion occur, like the lining of the intestines. Stratified squamous epithelium is more commonly found in areas subject to wear and tear, such as the skin. Stratified columnar epithelium is not typically found in the inner surface of blood vessels, making it an incorrect choice.

6. A decorative globe has a diameter of 25cm. What is its total surface area?

A. 1570 sq cm
B. 1963 sq cm
C. 2513 sq cm
D. 3142 sq cm

Correct answer: B

Rationale: Use the formula for surface area of a sphere: 4 * Ï€ * (radius)^2, where radius is half the diameter. Calculate the radius (12.5cm) and substitute: 4 * Ï€ * (12.5cm)^2 â‰ˆ 1963 sq cm.