ATI TEAS 7
Anatomy
1. In the context of cholesterol levels, LDL cholesterol is often referred to as:
- A. HDL or "good" cholesterol.
- B. LDL or "bad" cholesterol.
- C. Total cholesterol, encompassing both LDL and HDL
- D. VLDL, a type of triglyceride transported in the bloodstream
Correct answer: B
Rationale: The correct answer is B: LDL or "bad" cholesterol. LDL stands for low-density lipoprotein, which is often referred to as "bad" cholesterol because it can contribute to plaque buildup in the arteries, leading to a higher risk of heart disease. HDL, on the other hand, is known as "good" cholesterol because it helps remove LDL from the bloodstream. Total cholesterol (option C) encompasses both LDL and HDL levels but does not specifically refer to LDL cholesterol. VLDL (option D) is a different type of lipoprotein that transports triglycerides, not cholesterol. Understanding the distinction between LDL and HDL cholesterol is crucial for managing heart health.
2. Balance the following redox reaction in acidic solution: I⻠(aq) + Cr₂O₇²⻠(aq) -> I₂ (aq) + Cr³⺠(aq). Identify the oxidizing agent and reducing agent.
- A. I⻠is oxidized, Cr₂O₇²⻠is reduced
- B. I⻠is reduced, Cr₂O₇²⻠is oxidized.
- C. Both I⻠and Cr₂O₇²⻠are oxidized.
- D. Both I⻠and Cr₂O₇²⻠are reduced.
Correct answer: A
Rationale: . I⻠loses an electron (oxidation), Cr₂O₇²⻠gains electrons (reduction).
3. In the process of osmosis, the solvent moves from an area of...
- A. Low solute concentration to high solute concentration
- B. Hotter solution to colder solution
- C. Colder solution to hotter solution
- D. High solute concentration to low solute concentration
Correct answer: D
Rationale: In osmosis, solvent molecules move across a semi-permeable membrane from an area of low solute concentration to high solute concentration. This movement is driven by the desire to equalize the concentration of solutes on both sides of the membrane. As a result, option A is the correct answer because the solvent will naturally flow towards the area with a higher concentration of solutes in order to balance the concentrations on both sides of the membrane. Options B and C are incorrect as osmosis is not influenced by temperature differences. Option D is incorrect as the solvent does not move towards areas of high solute concentration in osmosis.
4. The ability of optical fibers to transmit light signals around bends is primarily due to:
- A. Reflection
- B. Refraction
- C. Diffraction
- D. Polarization
Correct answer: B
Rationale: The correct answer is B: Refraction. Optical fibers transmit light signals around bends primarily through the process of refraction. Refraction occurs when light passes from one medium to another, causing it to change direction. In optical fibers, the core material has a higher refractive index than the cladding, which causes light to be reflected internally along the fiber. This phenomenon allows light signals to travel through the fiber even around bends without significant loss. Reflection (Option A) involves light bouncing off a surface, which is not the main mechanism in optical fibers. Diffraction (Option C) refers to the bending of light waves around obstacles and is not the main reason for light transmission in optical fibers. Polarization (Option D) relates to the orientation of light waves, which is not the primary factor enabling light transmission around bends in optical fibers.
5. Which of the following is the main function of the small intestine?
- A. To store food and break it down into smaller pieces
- B. To absorb nutrients into the bloodstream
- C. To produce enzymes that help digest food
- D. To eliminate waste products from the body
Correct answer: B
Rationale: Rationale: The small intestine is a crucial part of the digestive system where the majority of nutrient absorption takes place. It is lined with tiny finger-like projections called villi that increase the surface area for absorption. The small intestine absorbs nutrients such as carbohydrates, proteins, fats, vitamins, and minerals from the digested food into the bloodstream to be transported to cells throughout the body for energy, growth, and repair. Options A, C, and D do not accurately describe the main function of the small intestine.
6. A diabetic patient's blood sugar is 180mg/dL. Their usual insulin dose is 1 unit per 40mg/dL above 100mg/dL. How much insulin should be administered?
- A. 2 units
- B. 3 units
- C. 4 units
- D. 5 units
Correct answer: B
Rationale: Rationale: 1. Calculate the excess blood sugar above 100mg/dL: 180mg/dL - 100mg/dL = 80mg/dL. 2. Determine the insulin dose based on the patient's usual insulin dose: 80mg/dL / 40mg/dL = 2 units. 3. Add the calculated insulin dose to the patient's usual insulin dose: 1 unit (usual dose) + 2 units (calculated dose) = 3 units. Therefore, the correct answer is 3 units of insulin should be administered to the diabetic patient with a blood sugar level of 180mg/dL.
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