Nursing Elites

1. The small intestine is where most of the chemical digestion and nutrient absorption occur. What is the finger-like projection in the small intestine that increases its surface area for absorption?

• A. Rugae
• B. Villi
• C. Microvilli
• D. All of the above

Correct answer: D

Rationale: The correct answer is D, 'All of the above.' The finger-like projection in the small intestine that increases its surface area for absorption is primarily the villi and microvilli. Villi are small, finger-like projections that line the inner wall of the small intestine, while microvilli are even smaller projections on the surface of the villi. Both structures significantly increase the surface area of the small intestine, allowing for more efficient absorption of nutrients. Rugae, on the other hand, are folds in the stomach lining that help with expansion when the stomach is full. Therefore, the rugae are not directly related to the increased surface area for absorption in the small intestine, making options A and B incorrect choices. Overall, options A, B, and C are all related to the structure of the small intestine but serve different functions, so the most appropriate answer is D, 'All of the above.'

2. A diabetic patient's blood sugar is 180mg/dL. Their usual insulin dose is 1 unit per 40mg/dL above 100mg/dL. How much insulin should be administered?

• A. 2 units
• B. 3 units
• C. 4 units
• D. 5 units

Correct answer: B

Rationale: Rationale: 1. Calculate the excess blood sugar above 100mg/dL: 180mg/dL - 100mg/dL = 80mg/dL. 2. Determine the insulin dose based on the patient's usual insulin dose: 80mg/dL / 40mg/dL = 2 units. 3. Add the calculated insulin dose to the patient's usual insulin dose: 1 unit (usual dose) + 2 units (calculated dose) = 3 units. Therefore, the correct answer is 3 units of insulin should be administered to the diabetic patient with a blood sugar level of 180mg/dL.

3. What is the process of breaking down fatty acids into acetyl-CoA, a key molecule in cellular respiration, called?

• A. Beta-oxidation
• B. Lipolysis
• C. Carbohydrate catabolism
• D. Nucleic acid catabolism

Correct answer: A

Rationale: Rationale: A) Beta-oxidation is the process of breaking down fatty acids into acetyl-CoA molecules. This process occurs in the mitochondria and is a crucial step in fatty acid metabolism for energy production. B) Lipolysis is the breakdown of fats into fatty acids and glycerol, but it does not specifically refer to the conversion of fatty acids into acetyl-CoA. C) Carbohydrate catabolism involves the breakdown of carbohydrates into glucose for energy production and is not directly related to the conversion of fatty acids into acetyl-CoA. D) Nucleic acid catabolism refers to the breakdown of nucleic acids into nucleotides and does not involve the conversion of fatty acids into acetyl-CoA.

4. The deeper layer of the skin, containing connective tissue, blood vessels, and nerve endings, is called the:

• A. Epidermis
• B. Dermis
• C. Hypodermis
• D. Stratum corneum

Correct answer: B

Rationale: The correct answer is B: Dermis. The dermis is the deeper layer of the skin that contains important structures such as connective tissue, blood vessels, and nerve endings. It plays a crucial role in providing support and nourishment to the epidermis, the outermost layer of the skin. The epidermis, option A, is actually the outermost layer responsible for protecting the body from environmental factors. The hypodermis, option C, is the deepest layer of the skin that primarily consists of fat and connective tissue. Stratum corneum, option D, is the outermost layer of the epidermis composed of dead skin cells. Therefore, the dermis is the correct answer in this case.

5. What checkpoint mechanism ensures all chromosomes are attached to the spindle fibers before anaphase begins?

• A. Prometaphase
• B. Prometaphase
• C. Cyclin degradation
• D. Sister chromatid cohesion

Correct answer: A

Rationale: Rationale: A) Prometaphase is the correct answer because it is the stage of mitosis where all chromosomes are attached to the spindle fibers before anaphase begins. During prometaphase, the nuclear envelope breaks down, allowing the spindle fibers to attach to the kinetochores of the chromosomes. This attachment is necessary for proper chromosome alignment and segregation during anaphase. B) Metaphase is incorrect because it is the stage where chromosomes are aligned at the metaphase plate but do not necessarily have all spindle fibers attached. C) Cyclin degradation is incorrect because it is a regulatory mechanism that controls the progression of the cell cycle but is not specifically related to ensuring all chromosomes are attached to spindle fibers. D) Sister chromatid cohesion is incorrect because it refers to the physical connection between sister chromatids that is maintained until anaphase, but it does not ensure that all chromosomes are attached to spindle fibers.

6. Which of the following statements about prions is TRUE?

• A. They are composed of proteins only
• B. They are easily destroyed by common disinfectants
• C. hey are a type of antibiotic
• D. They are a live organism

Correct answer: A

Rationale: Rationale: A) This statement is true. Prions are infectious agents composed entirely of protein, lacking nucleic acids such as DNA or RNA. They are known for causing neurodegenerative diseases in animals and humans. B) This statement is false. Prions are not easily destroyed by common disinfectants due to their unique structure and resistance to conventional sterilization methods. C) This statement is false. Prions are not a type of antibiotic. They are a distinct class of infectious agents. D) This statement is false. Prions are not live organisms but rather misfolded proteins that can induce abnormal folding in normal proteins, leading to disease.

Similar Questions